C:指针与函数
版权声明：原创作品，如需转载，请与作者联系。否则将追究法律责任。 |
1.指针作为形参 void exchange(int * const ptr1,int * const ptr2) { int temp; temp=*ptr1; *ptr1=*ptr2; *ptr2=temp; } void do_exchange() { int i1=100,i2=200,*p1=&i1,*p2=&i2; printf("i1=%i,i2=%i\n",i1,i2); exchange(p1,p2); printf("i1=%i,i2=%i\n",i1,i2); exchange(&i1,&i2); printf("i1=%i,i2=%i\n",i1,i2); } 2.从函数返回一个指针 struct linkedlist { int value; struct linkedlist *next; }; struct linkedlist *head; struct linkedlist *create() { struct linkedlist n1,n2,n3; n1.value=1; n2.value=2; n3.value=3; n1.next=&n2; n2.next=&n3; n3.next=NULL; head=&n1; return head; } struct linkedlist *find (struct linkedlist *listPtr,int target) { while(listPtr!=NULL) if(listPtr->value==target) return listPtr; else listPtr=listPtr->next; return NULL; } void do_find() { struct linkedlist *plist; int search; create(); printf("Enter value to locate: "); scanf("%i",&search); plist=find(head,search); if(plist!=NULL) printf("Found %i\n",plist->value); else printf("Not found\n"); } struct linkedlist *create();//返回一个结构体linkedlist指针 struct linkedlist *find (struct linkedlist *listPtr,int target);//返回一个结构体linkedlist指针 本文出自 “子 孑” 博客，转载请与作者联系！ 本文出自 51CTO.COM技术博客 |
zhangjunhd
博客统计信息
热门文章
最新评论
友情链接
